Almost got it...
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@ -16,22 +16,39 @@ def div_mod(A, B):
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if not B:
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raise ZeroDivisionError()
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a_len, b_len = len(A), len(B)
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if a_len < b_len or A[-1] < B[-1]:
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if a_len < b_len or (a_len == b_len and A[-1] < B[-1]):
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return [], A
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# Whew! Okay, we got all that out of the way.
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# A > B
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A_digits = A[-b_len:]
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A, A_digits = A[:-b_len], A[-b_len:]
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if -1 == cmp_digits(A_digits, B):
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# Because we know
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# A > B AND a_len >= b_len (aka len(A_digits))
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# if A_digits < B there must be at least one more
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# digit in A:
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assert a_len > b_len
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A_digits = A[-(b_len + 1):]
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A_digits.insert(0, A.pop())
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assert -1 < cmp_digits(A_digits, B)
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q, r = lil_divmod(A_digits, B)
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q, R = lil_divmod(A_digits, B)
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# So we have divided a prefix of A by B
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# resulting in a digit q of the answer Q
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# and a remainder R that must be extended
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# with the rest of the digits of A to make
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# a new number N
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N = A + R
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# which then must either be the remainder of
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# the whole thing if N < B...
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if -1 == cmp_digits(N, B):
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return [q], N
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# Otherwise, we find the rest of the digits
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# by
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Q, R = div_mod(N, B)
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Q.append(digit)
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return Q, R
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def lil_divmod(A, B):
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assert -1 < cmp_digits(A, B)
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@ -60,6 +77,7 @@ def int_to_list(i):
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return list(map(int, str(i)[::-1]))
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def list_to_int(A):
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if not A: return 0
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i = int(''.join(map(str, A[::-1])))
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assert i >= 0
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return i
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@ -88,9 +106,19 @@ def subtract(A, B):
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A = int_to_list(145)
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B = int_to_list(72)
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q, R = lil_divmod(A, B)
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print(f'divmod({list_to_int(A)}, {list_to_int(B)}) = ',
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q, list_to_int(R))
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##q, R = lil_divmod(A, B)
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##print(f'divmod({list_to_int(A)}, {list_to_int(B)}) = ',
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## q, list_to_int(R))
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def try_it(a, b):
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A = int_to_list(a)
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B = int_to_list(b)
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Q, R = div_mod(A, B)
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print(f'divmod({list_to_int(A)}, {list_to_int(B)}) = {list_to_int(Q)}, {list_to_int(R)}')
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try_it(145, 72)
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try_it(1450, 72)
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##print(cmp_digits([], []))
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