146 lines
2.8 KiB
Plaintext
146 lines
2.8 KiB
Plaintext
{
|
|
"cells": [
|
|
{
|
|
"cell_type": "markdown",
|
|
"metadata": {},
|
|
"source": [
|
|
"# Advent of Code 2017\n",
|
|
"\n",
|
|
"## December 4th\n",
|
|
"To ensure security, a valid passphrase must contain no duplicate words.\n",
|
|
"\n",
|
|
"For example:\n",
|
|
"\n",
|
|
"* aa bb cc dd ee is valid.\n",
|
|
"* aa bb cc dd aa is not valid - the word aa appears more than once.\n",
|
|
"* aa bb cc dd aaa is valid - aa and aaa count as different words.\n",
|
|
"\n",
|
|
"The system's full passphrase list is available as your puzzle input. How many passphrases are valid?"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "code",
|
|
"execution_count": 1,
|
|
"metadata": {},
|
|
"outputs": [],
|
|
"source": [
|
|
"from notebook_preamble import J, V, define"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "markdown",
|
|
"metadata": {},
|
|
"source": [
|
|
"I'll assume the input is a Joy sequence of sequences of integers.\n",
|
|
"\n",
|
|
" [[5 1 9 5]\n",
|
|
" [7 5 4 3]\n",
|
|
" [2 4 6 8]]\n",
|
|
"\n",
|
|
"So, obviously, the initial form will be a `step` function:\n",
|
|
"\n",
|
|
" AoC2017.4 == 0 swap [F +] step"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "markdown",
|
|
"metadata": {},
|
|
"source": [
|
|
"\n",
|
|
" F == [size] [unique size] cleave =\n"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "markdown",
|
|
"metadata": {},
|
|
"source": [
|
|
"The `step_zero` combinator includes the `0 swap` that would normally open one of these definitions:"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "code",
|
|
"execution_count": 2,
|
|
"metadata": {},
|
|
"outputs": [
|
|
{
|
|
"name": "stdout",
|
|
"output_type": "stream",
|
|
"text": [
|
|
"\n",
|
|
"==== Help on step_zero ====\n",
|
|
"\n",
|
|
"0 roll> step\n",
|
|
"\n",
|
|
"---- end (step_zero)\n",
|
|
"\n",
|
|
"\n"
|
|
]
|
|
}
|
|
],
|
|
"source": [
|
|
"J('[step_zero] help')"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "markdown",
|
|
"metadata": {},
|
|
"source": [
|
|
" AoC2017.4 == [F +] step_zero"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "code",
|
|
"execution_count": 3,
|
|
"metadata": {},
|
|
"outputs": [],
|
|
"source": [
|
|
"define('AoC2017.4 [[size] [unique size] cleave = +] step_zero')"
|
|
]
|
|
},
|
|
{
|
|
"cell_type": "code",
|
|
"execution_count": 4,
|
|
"metadata": {},
|
|
"outputs": [
|
|
{
|
|
"name": "stdout",
|
|
"output_type": "stream",
|
|
"text": [
|
|
"2\n"
|
|
]
|
|
}
|
|
],
|
|
"source": [
|
|
"J('''\n",
|
|
"\n",
|
|
"[[5 1 9 5]\n",
|
|
" [7 5 4 3]\n",
|
|
" [2 4 6 8]] AoC2017.4\n",
|
|
"\n",
|
|
"''')"
|
|
]
|
|
}
|
|
],
|
|
"metadata": {
|
|
"kernelspec": {
|
|
"display_name": "Python 2",
|
|
"language": "python",
|
|
"name": "python2"
|
|
},
|
|
"language_info": {
|
|
"codemirror_mode": {
|
|
"name": "ipython",
|
|
"version": 3
|
|
},
|
|
"file_extension": ".py",
|
|
"mimetype": "text/x-python",
|
|
"name": "python",
|
|
"nbconvert_exporter": "python",
|
|
"pygments_lexer": "ipython3",
|
|
"version": "3.8.3"
|
|
}
|
|
},
|
|
"nbformat": 4,
|
|
"nbformat_minor": 2
|
|
}
|