# [Newton's method](https://en.wikipedia.org/wiki/Newton%27s_method) Let's use the Newton-Raphson method for finding the root of an equation to write a function that can compute the square root of a number. Cf. ["Why Functional Programming Matters" by John Hughes](https://www.cs.kent.ac.uk/people/staff/dat/miranda/whyfp90.pdf) ```python from notebook_preamble import J, V, define ``` ## A Generator for Approximations To make a generator that generates successive approximations let’s start by assuming an initial approximation and then derive the function that computes the next approximation: a F --------- a' ### A Function to Compute the Next Approximation This is the equation for computing the next approximate value of the square root: $a_{i+1} = \frac{(a_i+\frac{n}{a_i})}{2}$ a n over / + 2 / a n a / + 2 / a n/a + 2 / a+n/a 2 / (a+n/a)/2 The function we want has the argument `n` in it: F == n over / + 2 / ### Make it into a Generator Our generator would be created by: a [dup F] make_generator With n as part of the function F, but n is the input to the sqrt function we’re writing. If we let 1 be the initial approximation: 1 n 1 / + 2 / 1 n/1 + 2 / 1 n + 2 / n+1 2 / (n+1)/2 The generator can be written as: 23 1 swap [over / + 2 /] cons [dup] swoncat make_generator 1 23 [over / + 2 /] cons [dup] swoncat make_generator 1 [23 over / + 2 /] [dup] swoncat make_generator 1 [dup 23 over / + 2 /] make_generator ```python define('gsra 1 swap [over / + 2 /] cons [dup] swoncat make_generator') ``` ```python J('23 gsra') ``` [1 [dup 23 over / + 2 /] codireco] Let's drive the generator a few time (with the `x` combinator) and square the approximation to see how well it works... ```python J('23 gsra 6 [x popd] times first sqr') ``` 23.0000000001585 ## Finding Consecutive Approximations within a Tolerance From ["Why Functional Programming Matters" by John Hughes](https://www.cs.kent.ac.uk/people/staff/dat/miranda/whyfp90.pdf): > The remainder of a square root finder is a function _within_, which takes a tolerance and a list of approximations and looks down the list for two successive approximations that differ by no more than the given tolerance. (And note that by “list” he means a lazily-evaluated list.) Using the _output_ `[a G]` of the above generator for square root approximations, and further assuming that the first term a has been generated already and epsilon ε is handy on the stack... a [b G] ε within ---------------------- a b - abs ε <= b a [b G] ε within ---------------------- a b - abs ε > b [c G] ε within ### Predicate a [b G] ε [first - abs] dip <= a [b G] first - abs ε <= a b - abs ε <= a-b abs ε <= abs(a-b) ε <= (abs(a-b)<=ε) ```python define('_within_P [first - abs] dip <=') ``` ### Base-Case a [b G] ε roll< popop first [b G] ε a popop first [b G] first b ```python define('_within_B roll< popop first') ``` ### Recur a [b G] ε R0 [within] R1 1. Discard a. 2. Use `x` combinator to generate next term from `G`. 3. Run `within` with `i` (it is a "tail-recursive" function.) Pretty straightforward: a [b G] ε R0 [within] R1 a [b G] ε [popd x] dip [within] i a [b G] popd x ε [within] i [b G] x ε [within] i b [c G] ε [within] i b [c G] ε within b [c G] ε within ```python define('_within_R [popd x] dip') ``` ### Setting up The recursive function we have defined so far needs a slight preamble: `x` to prime the generator and the epsilon value to use: [a G] x ε ... a [b G] ε ... ```python define('within x 0.000000001 [_within_P] [_within_B] [_within_R] tailrec') define('sqrt gsra within') ``` Try it out... ```python J('36 sqrt') ``` 6.0 ```python J('23 sqrt') ``` 4.795831523312719 Check it. ```python 4.795831523312719**2 ``` 22.999999999999996 ```python from math import sqrt sqrt(23) ``` 4.795831523312719